Answer: The sum of the equation is 18
Step-by-step explanation:
Define i as a unit vector in the eastern direction.
Define j as a unit vector in the northern direction.
Part I
Because the wind is blowing west, its velocity vector is
-23i mph or as (-23, 0) mph
Because the plane is traveling north, its velocity vector is
200j mph or as (0, 200) mph
Part II
The actual velocity of the plane is the vector sum of the plane and wind velocities.
That is,
200j - 23i or (-23, 200) mph
Part III
The ground speed of the plane is the magnitude of its vector.
The ground speed is
√[200² + (-23)²] = 201.32 mph
The ground speed of the plane is 201.3 mph (nearest tenth)
Not:
The direction of the plane is
tan⁻¹ 23/200 = 6.56° west of north.
Answer:
<em>I disagree with both solutions. The value of b that will make the expression correct is -30</em>
Step-by-step explanation:
Given the equation solved my Mai and Tyler expressed as:
2/5 b + 1 = -11
We are to check the veracity of the solutions;
2/5 b + 1 = -11
Subtract 1 from both sides of the expression
2/5 b + 1 -1 = -11-1
2/5 b = -12
Cross multiply
2b = -12 * 5
2b = -60
Divide both sides by 2
2b/2 = -60/2
b = -30
<em>Since the solution b = -25 and -28 does not tally with the gotten solution, I disagree with the both solutions</em>
