All categories

3 years ago

A sheet of glass has a density of 2.5 g/cm3. what is the density of the glass in kg/m3

Mathematics

2 answers:

asambeis [7]3 years ago

7 0

Answer:

this is ez

Step-by-step explanation:

2.5 g converted to kg: 2.5 g x 1 kg/1000 g = 0.0025 kg = 2.5x10-3 kg

cm3 converted to m3: 1 cm3 x 10-6 m3/cm3 = 1x10-6 m3

Thus, the conversion of 2.5 g/cm3 to kg/m3 would be 2.5x10-3 kg/10-6 m3 = 2.5x103 kg/m3 = 2500 kg/m3

kow [346]3 years ago

4 0

Answer:

2500

Step-by-step explanation:

(2.5 × 10^-3) ÷ (10^-6)

2.5 × 10³

2500 kg/m³

You might be interested in

What is the inverse of the function f(x) = 4x + 8

Y_Kistochka [10]

Answer:

let f(x)= y

y = 4x+8

x= 4y + 8

4y = x - 8

y = (x - 8)/4

Hope this helps.

7 0

3 years ago

Read 2 more answers

Evaluate and simplify <br> 4a - 2(a + b) + 1 = ? a=2 b=4

o-na [289]

Answer:

-3

Step-by-step explanation:

4(2)-2(2+4)+1=8-2(6)+1=9-12=-3

4 0

3 years ago

Read 2 more answers

Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical v

aliya0001 [1]

Answer:

$t=\pm 2.95$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

Data given

Confidence =0.99 or 99%

$\alpha=1-0.99=0.01$ represent the significance level

n =16 represent the sample size

We don't know the population deviation $\sigma$

Solution for the problem

For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

We know that $\alpha=0.01$ so then $\alpha/2=0.005$ and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:

"=T.INV(0.005;15)" and we got $t_{\alpha/2}=-2.95$ on this case since the distribution is symmetric we know that the other critical value is $t_{\alpha/2}=2.95$