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Scrat [10]
3 years ago
11

A sheet of glass has a density of 2.5 g/cm3. what is the density of the glass in kg/m3

Mathematics
2 answers:
asambeis [7]3 years ago
7 0

Answer:

this is ez

Step-by-step explanation:

2.5 g converted to kg: 2.5 g x 1 kg/1000 g = 0.0025 kg = 2.5x10-3 kg

cm3 converted to m3: 1 cm3 x 10-6 m3/cm3 = 1x10-6 m3

Thus, the conversion of 2.5 g/cm3 to kg/m3 would be 2.5x10-3 kg/10-6 m3 = 2.5x103 kg/m3 = 2500 kg/m3

kow [346]3 years ago
4 0

Answer:

2500

Step-by-step explanation:

(2.5 × 10^-3) ÷ (10^-6)

2.5 × 10³

2500 kg/m³

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What measure of central tendency is most affected by outliers?.
Elden [556K]

Answer: Mean

Mean is the only measure of central tendency that is always affected by an outlier.

hope this helps!

have a nice day!

8 0
2 years ago
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
3 years ago
The perimeter of a rectangle is 16.6km, and its area is 13.42km2. Find its length and width. length : km width : km
Otrada [13]

Answer:

l=5.12 & w=2.62

Step by step explanation:

A=l×w

13.42=lw

w=13.42/l

p = 2(l + w) \\ 16.6 = 2(l +  \frac{13.42}{l} ) \\ 16.6 = 2( \frac{ {l}^{2}  + 13.42}{l}) \\ 16.6 = 2(l + 13.42) \\ 16.6 = 2l + 26.84 \\ 2l = 26.84 - 16.6 \\ 2l = 10.24 \\ l =  \frac{10.24}{2}  \\ l = 5.12km

Since you have found the value of the length you can find the value.of the width.

w =  \frac{13.42}{l}  \\ w =  \frac{13.42}{5.12}  \\ w = 2.62km

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3 years ago
The graph of a relation must pass the vertical line test.<br><br> True or false
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The graph of a relation must pass the vertical line test.

True

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