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balandron [24]
3 years ago
6

Find the value of x that makes each equation true.

Mathematics
1 answer:
Luba_88 [7]3 years ago
8 0
1.\\\\ 3x-10=2\\3x=2+10\\3x=12\ \ /:3\\ x=\frac{12}{3}\\x=4\\\\2.\\\\ 8x-10=x+11\\8x-x=11+10\\7x=21\ \ /:7\\x=\frac{21}{7}\\x=7

3.\\\\ 5x-7=7x-17\\5x-7x=-17+7\\-2x=-10\ \ /:(-2)\\x= \frac{-10}{-2}\\x=5

4.\\\\ 3x+9=44-2x\\3x+2x=44-9\\5x=35\ \ /:5\\x=\frac{35}{7}\\x=5\\\\5. \\\\3x+6=x+2\\3x-x=2-6\\2x=-4\ \ /:2\\x=-\frac{4}{2}\\x=-2


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BartSMP [9]
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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kipiarov [429]

<u>Answer:</u>

a = 8.1

<u>Step-by-step explanation:</u>

Use the cosine rule:

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Substituting the values:

a = \sqrt{10^2 + 12^2 -2(10)(12) \space\ cos 42 \textdegree\ }

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4 0
1 year ago
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Vinil7 [7]

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The number of ways of arranging these 4 numbers = 4! = 24

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∴ option number 2 is correct.

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