Answer: (2,2), (4,2)
First, I subtracted 2y from both sides of the second equation. Then, I substituted -2y+6 in for x in the first equation (-2y+6)²+4y²=20. Then, I expanded 4y²-24y+16+4y²=20. Next, I combined like terms, and moved everything to one side 8y²-24y+16=0. Then, I factored out an 8, and then finished factoring 8(y-2)(y-1). This gives me my y-values, y=1,2. Next, I inserted each y-value into the second equation and got x=-2(1)+6 ---> x=4 (The first solution is (4,1). ) and x=-2(2)+6----->x=2 (The second solution is (2,2).
Answer:
<u>y-intercept</u><u> </u><u>is</u><u> </u><u>(</u><u>0</u><u>,</u><u> </u><u>-</u><u>2</u><u>1</u><u>)</u>
Step-by-step explanation:
For y-intercept, x = 0:
Answer:
-3x²+17x-20
Step-by-step explanation:
When you apply the distributive property (which you did correctly), you simply multiply each number or variable in which you have to distribute it to (which again you wrote correctly) and then you add them all together.
(3x)(-x)=-3x²
+
(3x)(4)=12x
+
(-5)(-x)=5x
+
(-5)(4)=-20
Add those and you will get your answer. Hope this helped :)
Answer:
See below.
Step-by-step explanation:
1.
5^2 + 12^2 = x^2
25 + 144 = x^2
169 = x^2
x = 13
2.
3^2 + x^2 = [sqrt(10)]^2
9 + x^2 = 10
x^2 = 1
x = 1
3.
1^2 + x^2 = 4^2
1 + x^2 = 16
x^2 = 15
x = sqrt(15)
4.
[sqrt(27)]^2 + x^2 = 6^2
27 + x^2 = 36
x^2 = 9
x = 3
5.
15/5 = c/sqrt(29)
5c = 15 * sqrt(29)
c = 3sqrt(29)
6.
26/13 = x/12
2 = x/12
x = 24
