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forsale [732]
3 years ago
8

50 POINTS for both questions

Mathematics
2 answers:
vitfil [10]3 years ago
7 0

Answer:

thats 5 points why u sayin 50

Step-by-step explanation:

love history [14]3 years ago
6 0

Answer:

3. i think 15.5

4. 140*

Step-by-step explanation:

in number 4, d is a vertical angle to the angle measured at 140.

in number 3, QV=SV, so 17=4x-1     18=4x    18/4=x   x=4.5

and TS=TQ, so 3(x) + 2 = 3(4.5) + 2 = 13.5 + 2 = 15.5 =TQ

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What is give an example of a unit rate used in a real world situation? Plz I'm literally so confused lol.
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Miles per hour. (mph)

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Someone please help!!!!!
Mumz [18]
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. </span></span>
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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
Which expression is equivalent to (5x^3)(2x)^3
Taya2010 [7]
Hello:
(5x^3)(2x)^3 = (5x^3)(2)^3(x)^3 = <span>(5x^3)8x^3=40x^6  ... (answer C)</span>
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