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forsale [732]
3 years ago
8

50 POINTS for both questions

Mathematics
2 answers:
vitfil [10]3 years ago
7 0

Answer:

thats 5 points why u sayin 50

Step-by-step explanation:

love history [14]3 years ago
6 0

Answer:

3. i think 15.5

4. 140*

Step-by-step explanation:

in number 4, d is a vertical angle to the angle measured at 140.

in number 3, QV=SV, so 17=4x-1     18=4x    18/4=x   x=4.5

and TS=TQ, so 3(x) + 2 = 3(4.5) + 2 = 13.5 + 2 = 15.5 =TQ

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HELP ASAP <br><br> Find the zeros of y = x^2 - 4x - 9 by completing the square.
Alla [95]

Answer: x= 2 + √ 13 ,2- √ 13

Step-by-step explanation:

Replace y with 0 and solve for x

4 0
3 years ago
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Ethan has 3/4 of a box of cereal. He gives 1/8 of the box to his little brother and Ethan eats 1/4 of the box, himself. What fra
riadik2000 [5.3K]

Answer:

<em>3/8 of the box cereal</em>

Step-by-step explanation: First you must convert 3/4, 1/8, and 1/4 so they have to same denominator. Four can go into eight two times, so you must multiply the numerator by two. So your new fractions are 6/8, 1/8, and 2/8. Now you must subtract 1/8 and 2/8 from 6/8. When you subtract 1/8 from 6/8 you get 5/8. Now subtract 2/8 from 5/8 and you get <em>3/8. </em>That is how you get the answer, I hope this helps you.


5 0
3 years ago
A watch loses 15 seconds every day how many minutes will it lose in 2 weeks.<br>​
REY [17]

2 weeks = 14 day

14 * 15 = 210 seconds

210/60=3 hours and 30 minutes or 3.5 hours.

8 0
2 years ago
An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect
Serggg [28]

Answer:

k = 1

P(x > 3y) = \frac{2}{3}

Step-by-step explanation:

Given

f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y  \leq x }  & { \text 0, { elsewhere. } } \end{array} \right.

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1

Where

{ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y  \leq x }

Substitute values for the interval of x and y respectively

So, we have:

\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1

Isolate k

k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1

Integrate y, leave x:

k \int\limits^2_{0} y {dx} \, [0,x/2]= 1

Substitute 0 and x/2 for y

k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1

k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1

Integrate x

k * \frac{x^2}{2*2} [0,2]= 1

k * \frac{x^2}{4} [0,2]= 1

Substitute 0 and 2 for x

k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1

k *[ \frac{4}{4} - \frac{0}{4} ]= 1

k *[ 1-0 ]= 1

k *[ 1]= 1

k = 1

Solving (b): P(x > 3y)

We have:

f(x,y) = k

Where k = 1

f(x,y) = 1

To find P(x > 3y), we use:

\int\limits^a_b \int\limits^a_b {f(x,y)}

So, we have:

P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy

P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy

P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0  dxdy

Integrate x leave y

P(x > 3y) = \int\limits^2_0  x [0,y/3]dy

Substitute 0 and y/3 for x

P(x > 3y) = \int\limits^2_0  [y/3 - 0]dy

P(x > 3y) = \int\limits^2_0  y/3\ dy

Integrate

P(x > 3y) = \frac{y^2}{2*3} [0,2]

P(x > 3y) = \frac{y^2}{6} [0,2]\\

Substitute 0 and 2 for y

P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}

P(x > 3y) = \frac{4}{6} -\frac{0}{6}

P(x > 3y) = \frac{4}{6}

P(x > 3y) = \frac{2}{3}

8 0
3 years ago
3x2 – 7x 7x = 4x – 8​
ratelena [41]

Answer:

x =−1−√93/23,−1+√93/23

Step-by-step explanation:

x=0.37581090…,−0.46276742...

5 0
3 years ago
Read 2 more answers
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