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julia-pushkina [17]

3 years ago

14

A rectangle is 8 inches long and 4 inches wide. A similar rectangle is 16 inches long. What is the width of the second rectangle

to the nearest inch?

1 answer:

Shkiper50 [21]3 years ago

4 0

8 × 2 = 16 so..... 4 × 2 = 8

the width is 8 inches

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Using the figure below, find the area of the circle.

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VladimirAG [237]

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6 0

3 years ago

To answer that question

Mars2501 [29]

First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45

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3 years ago