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3 years ago

14

Find f f'(x)=1+3sqrt(x) f(4)=25

1 answer:

wlad13 [49]3 years ago

6 0

It appears that you have a derivative and want to integrate...

dy/dx=1+3√x

y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...

y(4)=25=4+16/3+C

21=16/3+C

(63-16)/3=C

47/3=C so

f(x)=x+(2/3)x^(3/2)+47/3

f(x)=(3x+2x^(3/2)+47)/3

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