I conclude that the sum will be even because any even number can be represented by 2n where n is a whole number
and even numbers are 2 apart, so
the sum of the first 15 are
2n+2(n+1)+2(n+2) etc until we get to 2(n+14)
we can undistribute the 2 from all of them and get
2(n+n+1+n+2...n+14)
and we are sure that whatever is in the parenthasees is a whole number because whole+whole=whole
therefor, the sum is even
if you did want to find the sum then
an=2n
the 15th even number is 30
the first is 2
S15=15(2+30)/2=15(32)/2=15(16)=240
which is even
12000000 bytes is one frame, then you multiply that by 24 to get one second (288000000 bytes). Then I just multiplied that by 60 to get one minute (17.28 billion). After that I multiplied by sixty to get 1037000000000000 (1.037 trillion) so its 1.037 trillion bytes.
Answer:
47
Step-by-step explanation:
the lines are parrele which explains
why its 47
The answer would be it extends to infinity in both directions
Answer:
e=4
Step-by-step explanation:
