Question

Can someone help me with this? Its due in 30 minutes and I need help

Answer 1

Answer:

Step-by-step explanation:

when rotate counterclock wise 90 degrees:

(x,y)⇒(-y,x)

points                            (2,2)        (4,2)          (2,-1)          (4,-1)

CCW90 degrees           (-2,2)      (-2,4)         (1,2)           (1,4)

CCW 270 degrees        (2,-2)       (2,-4)        (-1,-2)         (-1,-4)

(x,y)⇒(y,-x)   the shape will be in quadrant 3 and 4

   

Answer 2

Answer:

Quadrants I and II.

O: (-2, 2)

N: (-2, 4)

M: (1, 4)

P: (1, 2)

Step-by-step explanation:

When rotating about the origin 90 degrees in a counterclockwise direction, focus on the coordinates of one point on the preimage at a time. So, the x-coordinate on the image will be the opposite of the y-coordinate of the preimage, and the y coordinate of the image will be the x-coordinate of the preimage. That sounds complicated so here is an example from the problem.

O is a point on the preimage. Its coordinates are (2, 2). To find the x-coordinate, take the opposite of the image's y-coordinate. The y-coordinate is 2, so it will be a -2 x-coordinate on the image. To find the y-coordinate on the image, take the x-coordinate of the preimage (O). The x-coordinate of O is 2, so the y-coordinate of the image will be 2. Combine those together and after a 90 degree counterclockwise rotation, you get a point of (-2, 2)