Solve for X. 5-3x= 12x + 4 X= 1/?

Mathematics

2 answers:

Wewaii [24]3 years ago

5 0

Solve for x:

5 - 3 x = 12 x + 4

Subtract 12 x from both sides:

5 + (-3 x - 12 x) = (12 x - 12 x) + 4

-3 x - 12 x = -15 x:

-15 x + 5 = (12 x - 12 x) + 4

12 x - 12 x = 0:

5 - 15 x = 4

Subtract 5 from both sides:

(5 - 5) - 15 x = 4 - 5

5 - 5 = 0:

-15 x = 4 - 5

4 - 5 = -1:

-15 x = -1

Divide both sides of -15 x = -1 by -15:

(-15 x)/(-15) = (-1)/(-15)

(-15)/(-15) = 1:

x = (-1)/(-15)

Multiply numerator and denominator of (-1)/(-15) by -1:

Answer: x = 1/15

butalik [34]3 years ago

4 0

5-3x=12x+4

5=15x+4

15x=1

x=1/15

You might be interested in

If the minute hand moves 30 degrees how much time has moved

Levart [38]

Has moved 30 minutes

4 0

3 years ago

X + y = -1<br> X - y = 7

enyata [817]

1: Solve for either x or y in one of the equations. So x + y = -1 is y = -x -1
2: substitute the new equation in the opposite equation. So x - (-x - 1) = 7
3: distribute the negative. X + x + 1 = 7
4: combine like terms. 2x + 1 = 7
5: solve for x. Subtract 1 on both sides. 2x = 6
6: divide by 2 to get x by itself. X = 3
7: plug the new value of x into one of the ORIGINAL equations. 3 + y = -1
8: solve for y. Subtract 3 on both sides.
Y = -4
9: the solution is written as (x,y) so the solution would be (3, -4)

4 0

4 years ago

Solve x2 + 15x = –56.

Black_prince [1.1K]

15x = 7x + 8x

$x^2+15x=-56\\\\ x^2+15x+56=0\\\\ x^2+7x+8x+56=0\\\\x(x+7)+8(x+7)=0\\\\ (x+7)(x+8)=0 \\\\ x=-7 \ or \ x=-8$