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3 years ago

Evaluate 7C6. (1 point) A. 9 B. 1 C. 5,040 D. 7

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

Https://us-static.z-dn.net/files/d04/41f003ca2080c4ffc698c0afa4904f6d.png

notsponge [240]3 years ago

5 0

$\bf _nC_r=\cfrac{n!}{r!(n-r)!}\qquad 
\begin{cases}
n=\textit{total elements}\\
r=\textit{partials}\\
--------\\
n=7\\
r=6
\end{cases}\implies _7C_6=\cfrac{7!}{6!(7-6)!}$

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3 years ago

Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.

sergij07 [2.7K]

Answer:

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Step-by-step explanation:

Given

$8x^{-10}y^6 - 2x^2y^{-8}$

Required

Simplify

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$8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}$

Take LCM

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Apply law of indices

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3 years ago

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VashaNatasha [74]

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3 years ago

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