PLEASE HELP : A rectangle has a length that is 15 more than its width. A second rectangle with a perimeter of 72 has a width tha t is 5 wider and a length that is 2 shorter than the first rectangle. Find the dimensions of the first rectangle.
1 answer:
Answer:
length = 24, width = 9
Step-by-step explanation:
Let's call the length and width of the first rectangle w + 15 and w respectively. This means that the length and width of the second rectangle is (w + 15) - 2 and w + 5 respectively. Since the perimeter of the second rectangle is 72, we can write:
2 * ((w + 15) - 2 + w + 5) = 72 because perimeter = 2 * (length + width)
(w + 15) - 2 + w + 5 = 36 (Divide by 2)
2w + 18 = 36 (Combine like terms)
2w = 18 (Subtract 18)
w = 9 (Divide by 2)
This means that the length and width are 24 and 9.
You might be interested in
f(x) = x²<span> - 5x + 1Answer: f(-3) = 25 (Answer C)
Answer:
Find the number which when divided by 35 gives the quotient 20 and remainder 18.
Step-by-step explanation:
Answer:
50.3
Step-by-step explanation:
area for circle formula=πr^2
r=4
π4^2 which is 50.3 rounded
2(n+7) =3n
Answer is 134.56, you’re welcome
