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3 years ago

Given h(x) = 2x – 3, find h(6).

Mathematics

2 answers:

Harrizon [31]3 years ago

5 0

Answer:

h(6) = 9

Step-by-step explanation:

h(x) = 2x – 3,

Let x = 6

h(6) = 2*6 -3

= 12 -3

= 9

lisov135 [29]3 years ago

3 0

Answer:

h(6) = 9

Step-by-step explanation:

To evaluate h(6), substitute x = 6 into h(x) , that is

h(6) = 2(6) - 3 = 12 - 3 = 9

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Please help and i have to be done with my work by tomorrow

e-lub [12.9K]

let length of painting = L
and width = W
from area = length times width
180 inch^2 = L times W
but L = 5/4 times W
180 inch^2 = 5/4 times W times W

W^2 = (4 x 180)/5
W = 12
but L = 5/4 x W
L = 5/4 x 12
L = 15

Answer: The dimensions of the painting are 12 x 15 inches.

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3 years ago

X^100+1 divide by x+1

timofeeve [1]

Answer:

x=-1

Step-by-step explanation:

$\frac{x ^{100} + 1 }{x + 1}$

$x + 1 = 0$

$x = - 1$

7 0

3 years ago

Pete has $2.67 in dimes and pennies.If he has $1.16 in pennies how many dimes does Pete have

mestny [16]

Answer:15 17

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .

5 0

3 years ago

A student concludes that the solution to the equation ( 2×+1+3=0 is×=4

Slav-nsk [51]

Answer:

x = -2

Step-by-step explanation:

2x + 1 + 3 = 0

2x + 4 = 0

x = -2

4 0

3 years ago