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2 years ago

Given h(x) = 2x – 3, find h(6).

Mathematics

2 answers:

Harrizon [31]2 years ago

5 0

Answer:

h(6) = 9

Step-by-step explanation:

h(x) = 2x – 3,

Let x = 6

h(6) = 2*6 -3

= 12 -3

= 9

lisov135 [29]2 years ago

3 0

Answer:

h(6) = 9

Step-by-step explanation:

To evaluate h(6), substitute x = 6 into h(x) , that is

h(6) = 2(6) - 3 = 12 - 3 = 9

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3 years ago

A cuboid with a volume of 924cm^3 has dimensions 4cm, (x+1)cm and (x+11). Show clearly that x^2+12x-220=0 solve the equation by

garik1379 [7]

Answer:

$x^2+12x-220=0$ -- Proved

$x = 10\ \ \ x = -22$

Step-by-step explanation:

Given

$Volume = 924cm^3$

$Dimension: 4cm; (x+1)cm; (x+11)cm$

Required

Show that $x^2+12x-220=0$

The volume is calculated as:

$4 * (x + 1) * (x + 11) = 924$

Open the brackets

$(4x + 4) * (x + 11) = 924$

$4x^2 + 44x + 4x + 44 = 924$

$4x^2 + 48x+ 44 = 924$

Collect Like Terms

$4x^2 + 48x+ 44 - 924=0$

$4x^2 + 48x -880=0$

Divide through by 4

$\frac{4x^2}{4} + \frac{48x}{4} -\frac{880}{4}=0$

$x^2+12x-220=0$

Solving further:

Expand the expression

$x^2 + 22x - 10x - 220 = 0$

Factorize:

$x(x + 22) - 10(x + 22) = 0$

$(x - 10)(x + 22) = 0$

Split:

$x - 10 = 0;\ \ \ x + 22 = 0$

$x = 10\ \ \ x = -22$

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2 years ago

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Mrrafil [7]

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We have been given that AE=BE and $\angle1\cong \angle2$ .

We can see that angle CEA is vertical angle of angle DEB, therefore, $m\angle CEA=m\angle DEB$ as vertical angles are congruent.

We can see in triangles CEA and DEF that two angles and included sides are congruent.

$\angle 1\cong \angle 2$

$AE=BE$

$\angle CEA\cong\angle DEB$ or $\angle 3\cong \angle 4$

Therefore, $\Delta CEA\cong \Delta DEB$ by ASA postulate.

Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.

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3 years ago

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