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3 years ago

Round 10,387 to the nearest thousand.

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

Answer:

10,000

Step-by-step explanation:

It is this because 387 is not greater than 500

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Two equations y=3/4x+1 and y=1/2x+b. They intersect at (4,2) what is b

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Answer:

b = 0

Step-by-step explanation:

Since,the equations y=3/4x+1 and y=1/2x+b intersect at (4,2)

So, plug x = 4 and y = 2 in equation y=1/2x+b, we find:

$2 = \frac{1}{2} \times 4 + b \\ \\ 2 = 2 + b \\ \\ 2 - 2 = b \\ \\ \purple{ \bold{ b = 0}}$

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2 years ago

What is the difference between complamentry and supplementry angles?

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3 years ago

Read 2 more answers

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Rudiy27

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3 years ago

I get

dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

$g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2$

For absolute minimum we take the minimum values of $x$ and $y$ .

$x_{minimum} =1\\y_{minimum}=1\\$

Plugging in the minimum values in the function.

$g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\$

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of $x$ and $y$ .

$x_{maximum} =2\\y_{maximum}=2\\$

Plugging in the maximum values in the function.

$g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\$

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

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4 years ago