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3 years ago

L want to know the sum result.10+67×2=?

Mathematics

2 answers:

cestrela7 [59]3 years ago

6 0

Answer:

154

Step-by-step explanation:

10 + 67 = 77

77 x 2 = 154

Volgvan3 years ago

3 0

Answer:

$144$

Step-by-step explanation:

Step 1: Multiply

$10 + (67 * 2)$

$10 + 134$

Step 2: Combine

$10 + 134$

$144$

Answer: $144$

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Nikitich [7]

Answer:

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2 years ago

What is the equation in point-slope form of a line that passes through the points (7,-8) and (-4,6)? HURRY!!!!!!

erastova [34]

Answer:

y - 7 = $\frac{14}{-11}$ (x + 8)

Step-by-step explanation:

Use the slope formula $\frac{y2 - y1}{x2-x1}$ to work out the slope

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3 years ago

A 35% dextrous solution (35 mg per 100 mL of solution) is given intravenously. Suppose a total of 1.17 L of the solution is give

ludmilkaskok [199]

Answer:

The flow rate in dextrous solution is 0.117 litres per hour

Step-by-step explanation:

Given:

The volume of fluid which passes per unit time = 1.17 Litres

Time Period = 10 hour

To Find:

The Flow rate per hour = ?

Solution:

Flow rate is defined as rate at which the "{volume of fluid which passes per unit time"

Here the Flow rate is = $\frac{\text{volume of fluid which passes per unit time}}{ time period}$

On substituting the values

The Flow rate is = $\frac{1.17}{10}$

The flow rate is 0.117 litres per hour

Thus 0.117 litres of dextrous solution flows per hour.

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2 years ago

Estimate the student's walking pace, in steps per minute, at 3:20 p.m. by averaging the slopes of two secant lines from part (a)

ehidna [41]

This question is incomplete, the complete question is;

A student bought a smart-watch that tracks the number of steps she walks throughout the day. The table shows the number of steps recorded (t) minutes after 3:00 pm on the first day she wore the watch.

t (min) 0 10 20 30 40

Steps 3,288 4,659 5,522 6,686 7,128

a) Find the slopes of the secant lines corresponding to the given intervals of t.

1) [ 0, 40 ]

11) [ 10, 20 ]

111) [ 20, 30 ]

b) Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part (a). (Round your answer to the nearest integer.)

Answer:

1) for [ 0, 40 ], slope is 96

11) for [ 10, 20 ], slope is 86.3

111) for [ 20, 30 ], slope is 116.4

b) the student's walking pace is 101 per min

Step-by-step explanation:

Given the data in the question;

t (min) 0 10 20 30 40

Steps 3,288 4,659 5,522 6,686 7,128

SLOPE OF SECANT LINES

1) [ 0, 40 ]

slope = ( 7,128 - 3,288 ) / ( 40 - 0

= 3840 / 40 = 96

Hence slope is 96

11) [ 10, 20 ]

slope = ( 5,522 - 4,659 ) / ( 20 - 10 )

= 863 / 10 = 86.3

Hence slope is 86.3

111) [ 20, 30 ]

slope = ( 6,686 - 5,522 ) / ( 30 - 20 )

= 1164 / 10 = 116.4

Hence slope is 116.4

Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part .

Since this is recorded after 3:00 pm

{ 3:20 - 3:00 = 20 }

so t = 20 min

so by average;

we have ( [ 10, 20 ] + [ 20, 30 ] ) /2

⇒ ( 86.3 + 116.4 ) / 2

= 202.7 /2

= 101.35 ≈ 101

Therefore, the student's walking pace is 101 per minutes

3 0

3 years ago

Degree 4; zeros: -4+5i, -1 multiplicity 2

Kazeer [188]

Answer:

$f(x) = [x^{2} + 8x + 41](x + 1)^{2}$

Step-by-step explanation:

If -4 + 5i is a root of a polynomial, then it's conjugate -4 - 5i will also be a root of the same polynomial.

Therefore, the polynomial has 4 degree, and zeroes are (- 4 + 5i), (- 4 - 5i) and -1 with multiplicity 2.

Hence, the polynomial will be

$f(x) = (x + 4 - 5i)(x + 4 + 5i)(x + 1)^{2}$

⇒ $f(x) = [x^{2} + 8x + (4 - 5i)(4 + 5i)] (x + 1)^{2}$

⇒ $f(x) = [x^{2} + 8x + 41](x + 1)^{2}$ (Answer)

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3 years ago

L want to know the sum result.10+67×2=?​

L want to know the sum result.10+67×2=?