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Vera_Pavlovna [14]
3 years ago
14

.Write a division equation so that it has a solution of -2

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0
Let’s take a random number such as 10, for example as the divisor of the equation.
Let’s take the dividend, or numerator of the fraction be x.
The solution of the fraction would be -2.

x/10 = -2
Or, x= -2 x 10
Or, x= -20

Therefore, -20/10 = -2
Ans: The division equation would be -20/10 = -2.
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ElenaW [278]
∠ADC = 112°
∠ADC =6x + 7 + 12x - 3

Equate both:
6x + 7 + 12x - 3 = 112

Solve for x :
6x + 7 + 12x - 3 = 112

Combine like terms:
18x + 4= 112

Take away 4 from both sides:
18x = 108

Divide both sides by 18:
x = 6

Find ∠ADB:
6x + 7 = 6(6) + 7 = 43


Answer: ∠ADB = 43°

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Find the sum. Express your answer in simplest form. 9a^2-5/b^2+2 + -2a^2+4/b^2+2
KonstantinChe [14]

Answer:

Step-by-step explanation:

\frac{9a^{2}-5}{b^{2}+2}+\frac{-2a^{2}+4}{b^{2}+2}=\frac{9a^{2}-5-2a^{2}+4}{b^{2}+2}\\\\=\frac{9a^{2}-2a^{2}-5+2}{b^{2}+2}\\\\=\frac{7a^{2}-3}{b^{2}+2}

5 0
3 years ago
Find all solutions to the following system of equations -y²+6y+x-9=0 ; 6y=x+27.Illustrate with a graph.
Dimas [21]

Answer:

The solution to the system is the pair (9, 6)

Step-by-step explanation:

Hi!

First, let´s write the system of equations:

-y² + 6y + x -9 = 0

6y = x +27

The solutions of the system are the pairs (x, y) that satisfy both equations.

Let´s take the second equation and solve it for x:

6y = x +27

Subtract 27 from both sides of the equation

6y - 27 = x

Now, we can replace x in the first equation and solve it for y:

-y² + 6y + x -9 = 0

-y² + 6y + 6y - 27 -9 = 0

-y² + 12y - 36 = 0

Notice that -y² + 12y - 36 = -(y - 6)², then:

-(y - 6)² = 0

y - 6 = 0

y = 6

(alternatively you can solve the quadratic equation using the quadratic formula).

Now let´s find the value of x:

x = 6y -27

x = 6·6 -27

x = 9

The solution to the system is the pair (9, 6)

Please see the attached figure. The point where the curves intersect is the solution to the system.

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3 years ago
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