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BARSIC [14]
3 years ago
6

The Bengals begin with a possession on their own 27-yard line. Four plays result in the following: gain of 6, loss of 12, a gain

of 2, loss of 7. On what yard line is the ball after the fourth play?
Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

The final position of the ball is on the 16 yard line.

Step-by-step explanation:

The final position of the ball after the fourth play is given by the initial position, in this case the 27-yard line, followed by a succession of sums and subtractions depending on the outcome of each play. For gains we sum and for losses we subtract. So we have:

final position = 27 + 6 - 12 + 2 -7

final position = 27 - 11

final position = 16

The final position of the ball is on the 16 yard line.

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A metal pipe is 70 cm in length. Its internal radius is 12mm and thickness is 1mm. If 1mm^3 of the metal weighs 0.05 gm, what is
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Step-by-step explanation:

we have to calculate the volume of 2 pipes, actually.

the inner, empty volume of the pipe with radius of 12mm.

and the complete pipe volume including the pipe wall, which adds 1mm to the radius (12+1 = 13mm).

and then we need to subtract the volume of the inner, hole part from the general pipe volume.

and that is then the volume of the actual pipe material, which we will then "translate" to weight based on the given ratio of 1/0.05 mm³/gm

so, what is the volume of a pipe ? it is actually a cylinder. it has a circular base area, and the length is, of course, the height.

the area of a circle is pi×r².

and the cylinder volume is base area times height :

pi×r²×height

also to remember : 1cm = 10mm

so, length = height = 70×10 = 700mm.

it is always important to use the same dimension of numbers when combining them in a calculation.

Vi (inner volume) = pi×12²×700 mm³ = pi×144×700 mm³

Vt (total volume) = pi×13²×700 mm³ = pi×169×700 mm³

Vt- Vi = (169 - 144)×pi×700 = 25×pi×700 mm³ =

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1 mm³ weighs 0.05 gm.

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the pipe weighs 2748.89 gm or 2.75 kg (1kg = 1000gm).

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