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3 years ago

4/10 as a proper fraction

Mathematics

2 answers:

erica [24]3 years ago

6 0

Answer: if you’re talking about simplifying then it would be 2\5.

Step-by-step explanation: all you do is divide two on 4 and 10 and your simplified fraction would be 2/5

stealth61 [152]3 years ago

5 0

You have to divide4and10

10divided by 4 is 2 with a remainder of 2

Keep your bottom number you get

4 2/10

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2b^2 +32b + 128 <br> Pls answer this

KengaRu [80]

Answer:

${2b}^{2} + 32b + 128$

Factor and get

$x = - 8$

8 0

3 years ago

Read 2 more answers

Plzzz help asapppppp what is the inverse of f if f(x)=^3 sqrt x-5

jasenka [17]

Hello from MrBillDoesMath!

Answer:

The first choice, y = x^3 + 5

Discussion:

Let

y = (x-5) ^ (1/3)

To find the inverse, sway x and y and then solve for y:

x = ( y - 5 )^(1/3) => cube both sides

x^3 = y - 5 => add 5 to both sides

x^3 + 5 = y

So the inverse is x^3 + 5, which is the first choice

Thank you,

MrB

4 0

3 years ago

Read 2 more answers

A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m,

BlackZzzverrR [31]

Answer:

301.4

Step-by-step explanation:

Volume of a cylinder=pi* $r^{2}$ *h. Assuming you want 3.14 for pi, we can substitue the 4m for r, 6 for h and 3.14 for pi.

V=3.14* $4^{2}$ *6

V=301.44

Since you want to round to nearest tenths, the answer is 301.4

8 0

4 years ago

A recipe calls for 1/2 cup of celery,2 1/3 of water and 3/4 cups of carrots. What the combined amont of these three ingredients?

lys-0071 [83]

Answer:

43/12

Step-by-step explanation:

First we must find a common denominator for all 3 fractions, 1/2 cup, 2 1/3 cup, and 3/4 cup all share 12 as a common denominator.

However, let's convert 2 1/3 cup into an improper fraction: there are 2 (3/3 cups) here multiply (3/3) and (2/1) you get 6/3. Finally, add the remaining 1/3 to 6/3 and you get 7/3.

Now, to get all these fractions to have the same common denominator.

(1/2) ×(6/6)=(6/12)

(7/3)×(4/4)=(28/12)

(3/4)×(3/3)=(9/12)

Add them all together and your answer is: (43/12)

7 0

4 years ago

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago