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Brums [2.3K]
3 years ago
12

Solve for AB. Round your answer to the nearest tenth if necessary.

Mathematics
1 answer:
OleMash [197]3 years ago
3 0
(5x+1)+(5x+2)=28
(because ab+bc=ac)
10x+3=28
10x=25
x=2.5
then plug 2.5 into ab equation:
5(2.5)+1=ab
ab=13.5
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On January 16 the temperature in Boston was -8 degrees at 4:00am and it when began to rise 3degrees every hours. What was the te
ANTONII [103]

Answer:

22 degrees

Step-by-step explanation:

6 0
3 years ago
What fraction of 20 is 18?
Vera_Pavlovna [14]

Remark

You have to read this carefully to know what way to write it.

One way you could write it would be

20 * x = 18 where x is  the fraction. Now all you need do is divide.

Divide both sides by 20

20/20 * x = 18/20

\text{x = } \dfrac{18}{20}

But you should reduce this fraction. The way to do that is to factor 18 and 20 into primes.

18: 2 * 3 * 3

20: 2 * 2 *5

Cancel out the Highest common factor or 2.

You are left with

\text{x = } \dfrac{18}{20} =\dfrac{2*3*3}{2*2*5}=\dfrac{3*3}{2*5} = \dfrac{9}{10} <<<< Answer

4 0
3 years ago
Read 2 more answers
Help plz I will give brainliest
larisa86 [58]

Answer:

180 Minutes or 3 Hours

Step-by-step explanation:

25 X 7 is 175

175 rounded by the nearest tenth is 180

180 Minutes.

8 0
2 years ago
Let f(x) = [infinity] xn n2 n = 1. find the intervals of convergence for f. (enter your answers using interval notation. ) find
inna [77]

Best guess for the function is

\displaystyle f(x) = \sum_{n=1}^\infty \frac{x^n}{n^2}

By the ratio test, the series converges for

\displaystyle \lim_{n\to\infty} \left|\frac{x^{n+1}}{(n+1)^2} \cdot \frac{n^2}{x^n}\right| = |x| \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = |x| < 1

When x=1, f(x) is a convergent p-series.

When x=-1, f(x) is a convergent alternating series.

So, the interval of convergence for f(x) is the <em>closed</em> interval \boxed{-1 \le x \le 1}.

The derivative of f is the series

\displaystyle f'(x) = \sum_{n=1}^\infty \frac{nx^{n-1}}{n^2} = \frac1x \sum_{n=1}^\infty \frac{x^n}n

which also converges for |x| by the ratio test:

\displaystyle \lim_{n\to\infty} \left|\frac{x^{n+1}}{n+1} \cdot \frac n{x^n}\right| = |x| \lim_{n\to\infty} \frac{n}{n+1} = |x| < 1

When x=1, f'(x) becomes the divergent harmonic series.

When x=-1, f'(x) is a convergent alternating series.

The interval of convergence for f'(x) is then the <em>closed-open</em> interval \boxed{-1 \le x < 1}.

Differentiating f once more gives the series

\displaystyle f''(x) = \sum_{n=1}^\infty \frac{n(n-1)x^{n-2}}{n^2} = \frac1{x^2} \sum_{n=1}^\infty \frac{(n-1)x^n}{n} = \frac1{x^2} \left(\sum_{n=1}^\infty x^n - \sum_{n=1}^\infty \frac{x^n}n\right)

The first series is geometric and converges for |x|, endpoints not included.

The second series is f'(x), which we know converges for -1\le x.

Putting these intervals together, we see that f''(x) converges only on the <em>open</em> interval \boxed{-1 < x < 1}.

6 0
2 years ago
Which ordered pair is a solution to the equation: y - 3 = x+2?
inysia [295]
Let's solve for x.<span><span>y−3</span>=<span>x+2</span></span>Step 1: Flip the equation.<span><span>x+2</span>=<span>y−3

</span></span>Step 2: Add -2 to both sides.<span><span><span>x+2</span>+<span>−2</span></span>=<span><span>y−3</span>+<span>−2</span></span></span><span>x=<span>y−5

</span></span>Answer:

<span>x=<span>y−<span>5</span></span></span>
3 0
3 years ago
Read 2 more answers
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