Question

Nolan begins a savings account with $100 at 2% interest according to the equation where Vn is the value of his account after x years. Anias invests $100 at 2% interest three years after Nolan.

Answer 1

Let's assume

amount invested is P

Since, we are given

Nolan invested equation as

$V_n=P(1.02)^x$

Anias invested equation as

$V_a=100(1.02)^{x-3}$

now, we can set them equal

$P(1.02)^x=100(1.02)^{x-3}$

now, we can solve for P

$P=\frac{100(1.02)^{x-3}}{(1.02)^x}$

now, we can simplify it

$P=100(1.02)^{x-3-x}$

$P=100(1.02)^{-3}$

$P=94.2322$

So, she needed to invest $94.2322 to have the same amount of money that she has three years later........Answer

Answer 2

Answer:

The answer for a question worded very similar to this on edge is actually 94.23 just did it

Step-by-step explanation: