Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.
Answer:
x=7/8
Step-by-step explanation:
x/8+3=10
x/8=7
x=7/8
Answer:
y = 97/3
Step-by-step explanation:
12y - 12 = 9y + 85
Subtract: 3y - 12 = 85
Add: 3y = 97
Divide: y = 97/3
Step-by-step explanation:
Easiest way is to use synthetic division, but I am going to use comparing coefficients because I have my phone:
x³ + 6x² - 5x
= (x - 2)(Ax² + Bx + C) + D
= Ax³ + (B - 2A)x² + (C - 2B)x + (D - 2C)
By Comparing Coefficients, we have
A = 1
B - 2A = 6
C - 2B = -5
D - 2C = 0
Solving, we have A = 1, B = 8, C = 11, D = 22.
Hence x³ + 6x² - 5x
= (x - 2)(x² + 8x + 11) + 22.