Seventh grade
1 answer:
You might be interested in
For this case we must resolve the following inequality:
Applying distributive property on the left side of inequality we have:
Subtracting 5 from both sides of the inequality:
Subtracting 4x from both sides of the inequality:
Thus, the result is
Answer:
<em>Note: It seems that you had forgotten to add the choices for this question. After a little research I am able to find the complete question, which is as follows:</em>
<em>Which ordered pair is on the line of the graph for y = 10x?</em>
A) (0, 10)
B) (1, 10)
C) (10, 1)
<em>D) (10, 10)</em>
<em>So, I am answering based on this complete question. Hopefully, it would help in terms of clearing your concept.</em>
Answer:
The ordered pair (1, 10) is on the line of the graph for y = 10x. So, the correct option is B) (1, 10). Also check the attached graph figure a.
.
Step-by-step explanation:
As the equation is given by
y = 10x
<em>for A) (0, 10) </em>
Put <em>(0, 10) in </em>y = 10x ⇒ 10 = 0
So, the ordered pair (0, 10) does not satisfy the question. So, option <em>A) (0, 10) is not true.</em>
<em> </em>
<em>for B) (1, 10) </em>
<em> </em>y = 10x
Put <em>(1, 10) in </em>y = 10x ⇒ 10 = 10
So, the ordered pair (1, 10) satisfies the question. So, option B<em>) (1, 10) is true. </em>Also check the attached graph figure a.
<em>for C) (10, 1) </em>
<em> </em>y = 10x
Put <em>(10, 1) in </em>y = 10x ⇒ 1 = 100
So, the ordered pair <em>(10, 1) does not</em> satisfy the question. So, option C<em>) (10, 1) is not true.</em>
<em>for D) (10, 10) </em>
<em> </em>y = 10x
Put <em>(10, 10) in </em>y = 10x ⇒ 10 = 100
So, the ordered pair <em>(10, 10) does not</em> satisfy the question. So, option <em>D) (10, 10) is not true.</em>
<em>So, </em><em>from all the given options, the ordered pair (1, 10) is on the line of the graph for y = 10x. So, the correct option is B) (1, 10). </em>Also check the attached graph figure a.
Keywords: graph, line, ordered pair
Learn more about ordered pair on the graph from brainly.com/question/12107132
#learnwithBrainly
