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Sergeu [11.5K]
3 years ago
11

Which is the correct factoring of

Mathematics
1 answer:
Igoryamba3 years ago
7 0

Answer:

C. (X+2)(x-6)

Step-by-step explanation:

  • x^2-4x-12
  • x^2-6x+2x-12
  • x(x-6)+2(x-6)
  • (x+2)(x-6)
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What type of proof explains the solution to a problem through a series of sentences?
Nadusha1986 [10]

Answer:

paragraph proof

Step-by-step explanation:

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3 years ago
How many 4/5 cup sugar bowls can be filled from 12 cups of sugar?
prisoha [69]
12 sugar / 4/5 sugar/bowls = 15 bowls. Hope you notice the conversion of units. 
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20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
2 years ago
Can you think of any 2x2 matrices d for which cd = dc for all 2x2 matrices c? give 2 different examples of such matricesd.
Ksju [112]
For any arbitrary 2x2 matrices \mathbf C and \mathbf D, only one choice of \mathbf D exists to satisfy \mathbf{CD}=\mathbf{DC}, which is the identity matrix.

There is no other matrix that would work unless we place some more restrictions on \mathbf C. One such restriction would be to ensure that \mathbf C is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking \mathbf D=\mathbf C^{-1} we'd get equality.
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3 years ago
A middle school took all of its 6th grade students on a field trip to see a ballet at a theater that has 2900 seats. The student
lesantik [10]

Answer:

34%

Step-by-step explanation:

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\dfrac{986}{2900} \times 100\% = 0.34 \times 100\% = 34\%

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