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laiz [17]
3 years ago
10

The three angles of a triangle are represented by (x+30),(4x+30),and (10x-30)

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
   the answer is x equal 100
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Write an algebraic equation that models the following statement.
8_murik_8 [283]
2(x +4)-6(q/9)

The slash represents a division sign.
5 0
2 years ago
7x + 3y + 2x<br><br> Please help me
Pachacha [2.7K]

Answer:

Your expression would be 9x + 3y

Step-by-step explanation:

Coefficients with the same variables can be added together

7 0
3 years ago
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3 years ago
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If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = -2. Give only the numerical answer. For example, if dy, dt = 4, type on
Nadya [2.5K]

Answer:

 \frac{dy}{dt}  = 102

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x  ... (i)

Differentiating equation (i) with respective to 'x'

    \frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)

Given x = -2

(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)

(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

                     \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

Given    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34

                  \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

substitute values    \frac{dx}{dt} = 3  and \frac{dy}{dx} = 34  

           ⇒        34 = \frac{\frac{dy}{dt} }{3 }

cross multiplication , we get

                      \frac{dy}{dt} = 34( 3 ) = 102

<u><em>Final answer</em></u>:-

 \frac{dy}{dt} = 34( 3 ) = 102

8 0
3 years ago
Helpppppppppppppppppppp
Sloan [31]

Answer:

Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

Step-by-step explanation:

We need to find sum of \frac{7x}{x^2-4} and \frac{2}{x+2}

Finding sum of  \frac{7}{x^2-4} and \frac{2}{x+2}:

\frac{7x}{x^2-4}+\frac{2}{x+2}

We know that x^2-4 =(x+2)(x-2)

Replacing x^2-4

\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}

So, Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

6 0
2 years ago
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