G = gallons d = days
10g = 3d
?g = 1d
1g = ?d
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for gallons in a day, divide 10g = 3d by 3
d = 10/3 gallons
3 and 1/3 gallons in a day
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for days per gallon, divide 10g = 3d by 10
g = 3/10 days
1 gallon lasts 3/10 of a day
( 4 / 5 )^-2 = ( 5 / 4 )^2 = 25 / 16 ;
Answer:
Input : 12
Output : -48
Step-by-step explanation:
Hope it helped
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