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KiRa [710]
3 years ago
13

What is the value of x?

Mathematics
1 answer:
lianna [129]3 years ago
7 0

10x-20+6x+8=180

16x-12=180 combine like terms

16x=192 add 12 to both sides

<em>x=12 </em>divide by 16

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What is the GFC of 40 and 60
Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

The highest common factor is 20

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A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all
Alex_Xolod [135]

Answer:

E(X) = 1*0.52+ 2*0.25 +3*0.23= 1.71

Now we can calculate the second moment with the following formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 1^2*0.52+ 2^2*0.25 +3^2*0.23= 3.59

And the variance is given by:

Var(X) = E(X^2) -E(X)

And replacing we got:

Var(X) = 3.59 -[1.71]^2 = 0.6659

And the standard deviation is just the square root of the variance:

Sd(X) = \sqrt{0.6659}= 0.816

Step-by-step explanation:

Previous concepts

For this case we define the random variable X =" how many children the couple will have" and we know the following distribution:

X           1            2             3

P(X)    0.52      0.250   0.230

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we can find the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) = 1*0.52+ 2*0.25 +3*0.23= 1.71

Now we can calculate the second moment with the following formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = 1^2*0.52+ 2^2*0.25 +3^2*0.23= 3.59

And the variance is given by:

Var(X) = E(X^2) -E(X)

And replacing we got:

Var(X) = 3.59 -[1.71]^2 = 0.6659

And the standard deviation is just the square root of the variance:

Sd(X) = \sqrt{0.6659}= 0.816

4 0
3 years ago
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