Keeping in mind that the element labeling is row,column, thus 2,1 simply means the 2nd row and 1st column, thus
The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is
In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then
It may be easier to start from
.. a(x +3)(x -1) = 0
.. a(x^2 +2x -3) = 0
The quadratic
.. ax^2 +bx +c = 0 will have solutions -3 and 1 for ...
.. a ≠ 0
.. b = 2a
.. c = -3a
Answer:
5/8
Step-by-step explanation:
5/8=0.6.25
0.625> all the other numbers