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egoroff_w [7]
2 years ago
10

What equation results from completing the square and then factoring? x2 + 10X = 15

Mathematics
1 answer:
Mandarinka [93]2 years ago
3 0

Answer:

C) (x + 5)² = 40

Step-by-step explanation:

Given the quadratic equation, x² + 10x = 15:

To complete the square, take the coefficient of the middle term (b), and divide it by 2<em>a</em>:

x² + 10x + [\frac{b}{2a}]^{2}  = 15 + [\frac{b}{2a}]^{2}

x² + 10x + [\frac{10}{2}]^{2}  = 15 + [\frac{10}{2}]^{2}  

x² + 10x + 5²  = 15 + 5²

x² + 10x + 25 = 40

The trinomial on the left-hand side of the equation provides a perfect square binomial factors: <em>u</em>² + 2<em>uv</em> + v² = (<em>u</em> + <em>v</em>)²

x² + 10x + 25 = 40

(x + 5)²  = 40

Therefore, the correct answer is Option C)  (x + 5)²  = 40

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\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

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\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

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Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

4 0
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