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Effectus [21]
2 years ago
7

Solve 6x(6x) + 11x - 35 = 0

Mathematics
2 answers:
sergeinik [125]2 years ago
6 0
6x(6x) + 11x - 35 = 0
36x^2 + 11x - 35 = 0
36x^2 + 11x = 35
  
-11 + or -  square root 11^2 - 4 (36) (-35)
                      divided by 
                         2 * 36 

-11 + or - square root 5161
                   divided by
                        72

-11 + or - 71.84
     divided by
          72

There are two answers to the problem:
-11 + 71.84 / 72 = -10 rounded
-11 - 71.84 / 72 = -12. rounded
welcome :/


Murljashka [212]2 years ago
4 0
36x^2 + 11x - 35=0\\\\ \frac{-b \pm  \sqrt{ b^2 -4( a)(c)} }{2(a)}\\\\  \frac{-11\pm  \sqrt{11^2 -4(36)(-35)} }{2(36)}\\ \\   \frac{-11\pm  \sqrt{5161 } }{72}\\\\\\ x = 0.8450013919812116\\\\ \text{   } x  = -1.1505569475367672
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