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shutvik [7]
3 years ago
13

What is the solution to the system of linear equations? −9x+4y=55 −11x+7y=82

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

the correct answer would be

(3,7)

7(-9+4y=55)

-4(-11+7y=82)

63x+28y=385

44x-28y=-328

19x         =57

x=3


63(3)+28y=385

189+28=385

28y=196

y=7


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I really need help rn T_T plz help me out!
pshichka [43]

Answers:

  • The lengths of sides PQ and RS are <u>   13   </u>
  • The lengths of sides QR and SP are <u>   </u><u>20  </u>

This is a 13 by 20 rectangle.

============================================================

Explanation:

Refer to the drawing below.

Let x be the length of side SP. Since we're dealing with a rectangle, the opposite side is the same length. Side QR is also x units long.

We're told that RS = SP - 7 which is the same as saying RS = x-7

We also know that PQ = x-7 as well because PQ is opposite side RS.

In short, we have these four sides in terms of x

  • PQ = x-7
  • QR = x
  • RS = x-7
  • SP = x

as shown in the drawing. The four sides add up to the perimeter of 66.

PQ+QR+RS+SP = perimeter

PQ+QR+RS+SP = 66

(x-7)+x+(x-7)+x = 66

4x-14 = 66

4x = 66+14

4x = 80

x = 80/4

x = 20

Use this x value to find the unknown side lengths.

  • PQ = x-7 = 20-7 = 13
  • QR = x = 20
  • RS = x-7 = 20-7 = 13
  • SP = x = 20

In short, this is a 13 by 20 rectangle.

-----------------

Check:

perimeter = side1+side2+side3+side4

perimeter = PQ+QR+RS+SP

perimeter = 13+20+13+20

perimeter = 33+33

perimeter = 66

The answer is confirmed.

4 0
3 years ago
A cell phone company offers you a plan that chargers a flat rate of $25 per month for 200 minutes of airtime .The rate for any t
Blizzard [7]
Y=0.12x+25 would be the correct answer

3 0
4 years ago
The scale in a drawing is 2 cm : 5 m. What are the length and width of the actual room? Find the area of the actual room. 10 cm
Radda [10]
10/2= 5 so 5: 5 x 5 so the length is 25. 6/3 = 2  so 2: 2 x 5 = 10.
Area is length times width. 25 x 10= 250
3 0
4 years ago
Pls help me this pls
Sunny_sXe [5.5K]

Answer:

RGDF

RGDF

Step-by-step explanation:

rgdf

rgdf

RGDF

7 0
3 years ago
What is the probability of drawing a diamond from a standard deck of cards on a second draw, given that a diamond was drawn on t
Charra [1.4K]
This problem is all about probability. It is the study of predicting the likelihood or chances of a certain event to happen out of all the possibilities. It is always expressed as a part of a whole. Therefore, the answer is either in fraction or in percentage. 

A standard deck of card consists of 52 cards all in all. There are 13 diamond cards within the deck. So, the probability of getting a diamond card is 1/52. But we are given with a conditional probability. The first draw is sure to pick a diamond. So, the probability for this is 1 or 100%. But we should multiply this to the second scenario which is the 2nd draw. If you picked a card already, that means the total number of cards is 52 less 1. Also, because you already picked a diamond in the first draw, the diamond cards left in the deck is 13 less 1. Therefore, the probability of getting a diamond card in the second draw is

Probability = 1 × 12/51
Probability = 12/51
7 0
3 years ago
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