To be a right triangle, the hypotenuse^2 must equal side1^2 + side2^2
Only set 2 meets these conditions
8, sq root (29), sq root (35) then squaring these:
64, 29, 35
64 = 29 + 35
Answer:
A quadrilateral with no sides parallel
Answer:
f(x)= (x-3)^2-3
Step-by-step explanation:
Vertex Form: y= a(x-h)^2+k
a is the reflection
h and k are the vertex so in an ordered pair (x,y) = (h,k)
Since it is translating 3 units down it is going to be a negative 3. If it was translating up it would be positive 3. This represents the "k" because it is moving on the y-axis.
Since it is translating 3 units to the right it is going to be positive 3. If it was translating left it would be negative 3. This represents the "h" because it is moving on the x-axis.
After plugging it into the vertex form formula: f(x)= (x-3)^2-3
*notice when I plugged the "h" in it became negative because x-(3)= x-3*
Answer:
The true options are:
2) Has exactly one pair of parallel sides
4) Has exactly one pair of congruent sides
5) Both pairs of opposite sides are congruent
7) There are right angles at all 4 vertices
9) The diagonals are congruent
10) The diagonals bisect each other.
<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>
