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3 years ago

Help:/

1 answer:

3 0

The answers are the following:
1. 4.8x100^7 is not in scientific notation.
No; it is not written as a number times a power of 10. It should not be "times 100" because in scientific notation, the highest number to be expanded by the degree is 10.

2. 5.1x10^-8 is in scientific notation.
yes; the number is written in scienfic notation. This is because it has a base number and multiply to x10^-8 which is the exponent indicating that the expanded value is 0.000000051

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The measurements of a rectangular prism are shown.

avanturin [10]

In a rectangular prism, surface area is calculated by multiply all the faces of the prism that you can touch

Becuase there's four faces that have the measurement of 5*3, you do 4(5*3) and because there's only two faces that have the measurement of 3*3, you do 2(3*3)

Which becomes 4(5*3)+2(3*3) which is 78

3 0

3 years ago

Ill give you brainlyist

salantis [7]

Answer:

Step-by-step explanation:

because they are vertical angles they are equal to each other so we write the equation 132=5x+7

step 1 subtract each side by 7

125=5x

step 2 divide each side by 5

x=25

7 0

3 years ago

Match the expression on the left with the correct simplified expression on the right.

andriy [413]

Given: The expression below

$\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}$

To Determine: The matching expression to the given expressions

Solution

Let us simplify each of the expressions using exponents rule

$\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}$

Applying the exponent rule 1 above to the given expressions

$\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}$ $\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}$

Applying the exponent rule 2

$\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8$ $\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2$

Let us not apply exponent rule 1 above

$(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}$ $(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4$

Hence, the matching is as shown below

8 0

2 years ago

C(n)=-6+5(n-1) find the 8th term in this sequence

Goryan [66]

Answer:

Just replace n by 8 ===> C(8) = -6+5(8-1) = - 6 + 5x7 = -6+35 = 29

Step-by-step explanation:

We have been given a sequence formula. We are asked to find the 8th term of our given sequence.

We know that an arithmetic sequence is in form A_n=a_1+(n-1)d, where,

A_n=\text{ nth term of sequence},

A_1=\text{ 1st term of sequence},

n = Number of terms in sequence,

d = Common difference.

To find the 8th term of our given sequence, we will substitute n=8 in our given formula.

c(n)=-6+5(n-1)

c(8)=-6+5(8-1)

c(8)=-6+5(7)

c(8)=-6+35

5 0

3 years ago

Uhhh I am struggling with this question algebra 1

Olin [163]

Answer:

-2x^2 +16x -8

Step-by-step explanation:

Oh s-

Like terms i guess Same variable you can substract. Remember you only substract from 1 number not from all.

-2x^2 stays the same as there is no like term

9x - (-7x)

-2 - (6)

-2x^2 + 9x+ 7x -2-6

-2x^2 +16x -8

4 0

3 years ago