Can anyone help me in this question!!

The normal distribution common core algebra 2 homework answers

natima [27]

The normal distribution common core algebra 2 example is solve for the calculation that leads to the answer in x₁ = 66 inches (image attached)

<h3>What is this algebra about?</h3>

Algebra is known to be an aspect of mathematics that handles symbols and the laws for manipulating the given symbols.

Note that x₁ = 66 inches.

= 66 - 62/ 3.2

= 1.25

Therefore the answer is 1.25.

Learn more about algebra from

brainly.com/question/723406

#SPJ1

6 0

1 year ago

The following are the advantages of partnership except one

Aliun [14]

C. their liability is limited by each partner's share of the business.

Hope it helps!

Brainliest would be nice but of course you don’t gotta :)

6 0

2 years ago

What is main difference between the SAT-I and SAT-II?

Mrrafil [7]

Originally, the SAT I was meant to test aptitude and the SAT II was meant to test achievement. That is to say, one tested what you were capable of and the other tested what you knew. But when the College Board moved away from the idea that the SAT I tests innate ability, they framed it as a reasoning test, making the difference between the two less defined.

With the latest changes, the SAT I (now just the SAT) is more focused than ever testing knowledge rather than logic. At this point, I would say that the SAT tests general knowledge and and the Subject Tests assess topical knowledge.

5 0

2 years ago

A bat emits a sound at a frequency of 3. 00 × 104 hz as it approaches a wall. The bat detects beats such that the frequency of t

OLga [1]

Taking into account the Doppler efect, the speed of the bat is closest to 5.02 $\frac{m}{s}$ .

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

$f1=f\frac{v+-vR}{v+-vE}$

Where:

f1, f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 340 m/s
vR, vE: Speed of the receiver and the sender respectively. Its unit of measure in the S.I. is the m/s
±, ∓:

We will use the + sign:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

We will use the sign -:

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

f1= 30,000 Hz + 900 Hz= 30,900 Hz
f= 30,000 Hz
v= 340 m/s
vE=vR= vbat
Receiver approaches the sender

Replacing in the expression is considered the general case of the Doppler effect:

$30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}$

Solving:

$\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}$

$1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}$

1.03×( 340 $\frac{m}{s}$ -vbat)= 340 $\frac{m}{s}$ + vbat

1.03×340 $\frac{m}{s}$ - 1.03×vbat= 340 $\frac{m}{s}$ + vbat

350.2 $\frac{m}{s}$ - 1.03×vbat= 340 $\frac{m}{s}$ + vbat

350.2 $\frac{m}{s}$ - 340 $\frac{m}{s}$ = vbat + 1.03×vbat

10.2 $\frac{m}{s}$ = 2.03×vbat

10.2 $\frac{m}{s}$ ÷ 2.03 = vbat

In summary, the speed of the bat is closest to 5.02 $\frac{m}{s}$ .

Learn more about the Doppler effect:

6 0

1 year ago

Which type of burn is BEST described as having reddish skin, white border, and some pain? A. first-degree burn B. second-degree

alexgriva [62]

Answer:

I believe it's B - Second-Degree Burns

Explanation:

A first degree burn would be like keeping your finger over a flame for a little too long, it'll cause red skin and some pain, but not the white boarder. Third degree burns would be like holding onto metal left in burning temperatures, touching lava, it'll burn all the way down to the fat tissue, causing emese pain. Fourth degree burns are horrible, the skin turns black, it burns past the fat tissue, no way it would cause only "some" pain

6 0

2 years ago