3 years ago

What is the degree of the monomial? 3x^10

1 answer:

8 0

The degree is 0. I don't know how to solve it I just used a website that allows you to answer things like this. <span />

You might be interested in

Solve for z. Please show your work. 8z = 2z + 18

Nataly_w [17]

Answer:

x = 3

Step-by-step explanation:

8z = 2x + 18

6x = 18

x = 3

4 0

3 years ago

Read 2 more answers

36 games of 12 losses as a unit rate

denis23 [38]

36:12 is the answer

4 0

3 years ago

Read 2 more answers

Which points are a solution to the equation y = 5x - 4?

denis-greek [22]

Answer:

The answer are

(0,_4)

(2,6)

(3,11)

4 0

3 years ago

URGENT!! Really need help on this test

Anuta_ua [19.1K]

Answer:

x=17

Step-by-step explanation:

53+(2x+3)=90

7 0

3 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

3 years ago