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navik [9.2K]
4 years ago
7

A pool is in the shape of a rectangular prism. On Monday, water was pumped out of the pool at a constant rate, starting at 12:00

pm. At 12:15 pm, the water in the pool was 45 inches deep. At 12:35 pm, the water in the pool was 41 inches deep.
Part A
How many inches does the depth of the water decrease each minute?

Part B
Write an equation that represents y, the depth of the water (in inches) after x minutes.
Mathematics
1 answer:
stepladder [879]4 years ago
6 0

Answer:

um idk.....

Step-by-step explanation:

sorry

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Step-by-step explanation:

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Car 1: exponential as the projected value is not decreasing by the same amount each year

Car 2: linear as the projected value decreases by the same amount each year ($1000)

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<u>Car 1</u>

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NB We have to change x to "x-1" since we are told in the table that <u>after</u> 1 year the car's value is 18500.

<u>Car 2</u>

General form of linear function:  y=mx+b

m=\dfrac{\textsf{change in} \ y}{\textsf{change in} \ x}=\dfrac{17500-18500}{2-1}=-1000

y-y_1=m(x-x_1)

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Car 1 after 10 years: \implies f(10)=18500(0.94)^{10-1}=\$10,600.40

Car 2 after 10 years: \implies f(10)=-1000(10)+19500=\$9,500

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Yes, there will be a significant difference of $1,100.40 which is approx 10% of the value of the cars after 10 years.

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