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3 years ago

10

Ratios that are equivalent to 7: 6.

1 answer:

Alex3 years ago

7 0

Step-by-step explanation:

21:18=7:6

42:36=7:6

63:54=7:6

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You kayak up a river at a rate of 36 feet every 30 seconds. You kayak 304 feet every 2 minutes on the way back down the river. H

Vikki [24]

Answer:

400

Step-by-step explanation:

too lazy

5 0

3 years ago

If m<4=63, what is m<1?

Stella [2.4K]

Answer:

m<11=5.75

Step-by-step explanation:

<u>since you already know what m<4 is </u>

<u>we just have to divide the result (63) by 4</u>

<u>63%4=15.75 </u>

therefore m<1= 15.75

4 0

3 years ago

Can someone please help me

Anettt [7]

Answer:

y = -6x + 9/4

Step-by-step explanation:

y = mx + b

m= -6

b 9/4

7 0

3 years ago

Where is the maximum value for this quadratic function?

ANEK [815]

The answer to this question is c

3 0

4 years ago

Read 2 more answers

Find the velocity and position vectors of a particle that has the given acceleration and the given initial velocity and position

stira [4]

Answer:

$v(t) = (2t+1) \mathbb{i} +3t^2 \mathbb{j} +4t^3 \mathbb{k}$

$r(t) = (t^2+t) \mathbb{i} +(t^3+2) \mathbb{j} +(t^4 - 3) \mathbb{k}$

Step-by-step explanation:

The velocity vector is the integral of the acceleration vector i.e.

$v(t) = \int a(t) dt$

$v(t) = \int (2 \mathbb{i}+6t \mathbb{j} 12t^2 \mathbb{k}) dt$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + C_1$

When $t=0$ , $v(0) = \mathbb{i}$ . Inserting these values in $v(t)$ ,

$C_1= \mathbb{i}$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + \mathbb{i}$

$v(t) = (2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}$

The position vector is the integral of the velocity vector i.e.

$r(t) = \int v(t) dt$

$r(t) = \int ((2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}) dt$

$r(t) = (t^2+t) \mathbb{i}+t^3 \mathbb{j} t^4 \mathbb{k} + C_2$

When $t=0$ , $r(t) =2\mathbb{j}-3\mathbb{k}$ . Inserting these values in $r(t)$ ,

$C_2=2\mathbb{j}-3\mathbb{k}$

$r(t)= (t^2+t) \mathbb{i}+t^3 \mathbb{j}+ t^4 \mathbb{k} + 2\mathbb{j}-3\mathbb{k}$

$r(t) = (t^2+t) \mathbb{i}+(t^3+2) \mathbb{j}+ (t^4-3) \mathbb{k}$

5 0

4 years ago