Question

carlos has a tub that can hold 2 1/4 L, which is a third of what Corey's container can hold. Corey's container is half full of water. How much water does he have?

Answer 1

Answer:

$3\frac{3}{8}$ liters

Step-by-step explanation:

We have been given that Carlos has a tub that can hold 2 1/4 L, which is a third of what Corey's container can hold.  

This means that Corey's container will have 3 times the water that Carlos's tub can hold.

Let us convert 2 1/4 into mixed fraction.

$2\frac{1}{4}=\frac{9}{4}$

Now we need to find 3 times of $\frac{9}{4}$ liters as:

$\frac{9}{4}\times 3=\frac{9\times 3}{4} = \frac{27}{4}$

So Corey's container can hold $\frac{27}{4}$ liters of water.

We are also told that Corey's container is half full of water. So to find amount of water, we will divide total amount of water by 2 as:

$\frac{27}{4}\div 2$

$\frac{27}{4}\div \frac{2}{1}$

Convert division problem into multiplication problem by flipping the 2nd fraction.

$\frac{27}{4}\times \frac{1}{2}$

$\frac{27}{4\times 2}=\frac{27}{8}$

$\frac{27}{8}=3\frac{3}{8}$

Therefore, Corey's container has $3\frac{3}{8}$ liters of water.