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Dafna11 [192]
3 years ago
10

#7) Who is correct?

Mathematics
1 answer:
Kryger [21]3 years ago
8 0
I think Faye is correct
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For f(x)=2x+1 and g(x)=x+14 , find (g o f) (x).
Nataliya [291]

Answer:

(g o f) (x) = 2x + 16

Step-by-step explanation:

" (g o f) (x) )" is called "the composition of f and g."

Evaluating this involves substituting the function f(x) = 2x + 1 for x in g(x) = x+14:

(g o f) (x) = 2(x+1) + 14, or

(g o f) (x) = 2x + 2 + 14, or

(g o f) (x) = 2x + 16

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3 years ago
What is the domain and range for this graph?
Kay [80]
Domain: -∞, <span>∞
range: -5,</span><span>∞
(the commas mean through; ex.; -5,</span><span>∞..... that means negative 5 thru infinity)</span>
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4 years ago
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The answer is 539.01 :)
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2 years ago
Does (–3, 17) make the equation y = 6x + –1 true?
telo118 [61]

Answer:

ture

Step-by-step explanation:

Read the article and review the phases of mitosis.

Mitosis

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2 years ago
Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
3 years ago
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