Answer:
13.60 See the note below.
Step-by-step explanation:
Remark
This is just the reverse of the question you just did. This time you are trying to solve for c
Givens
Solution
c^2 = a^2 + b^2 Substitute the givens.
c^2 = 8^2 + 11^2 Expand
c^2 = 64 + 121 Combine the right side by adding
c^2 = 185 Take the square root of both sides.
sqrt(c^2) = sqrt(185) Complete the operation
c = 13.601 Round to the nearest 1/100 th
c = 13.60 Note: the zero must be there or the answer does not show the nearest 1/100 th
Answer:
A(0,3) B(3,4) C(2,1)
Step-by-step explanation:
when reflecting you just the change the sign if either the X or the Y. in this case it's the Y
Here is your answer
Money saved on each successive day is-
$3, &5, $7....
Clearly it forms an AP,
where
a1= 3
common difference, d= 2
n=20
So,
using formula
Tn= a1+(n-1)d
T20= 3+(20-1)2
= 3+ 19×2
= 3+ 38
=41
So, money saved on August 20= $41
Sum of money saved upto August 20 =
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
= $440
HOPE IT IS USEFUL
