#7) Who is correct?

2 qts for every 50 gal of water i just want to use 15 gal of water so how much do i use

Papessa [141]

The amount of qts to use for 15 gals is 0.6qts

Proportion and ratio

Ratio are written as quotient of 2 integers

Given that 2 qts for every 50 gal of water, this is written as;

2qts = 50 gals

In order to calculate for 15gal, we will have:

x = 15gals

Take the ratio

2/x = 50/15

50x = 30

x = 3/5

x = 0.6qts

Hence the amount of qts to use for 15 gals is 0.6qts

Learn more on qts to gallons here: brainly.com/question/466814

#SPJ1

7 0

3 years ago

Mateus’s bank issued an advertisement saying that 90\%90%90, percent of its customers are satisfied with the bank’s services. Si

densk [106]

Answer:

The probability of getting a sample with 80% satisfied customers or less is 0.0125.

Step-by-step explanation:

We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.

Let $\hat p$ = sample proportion of satisfied customers

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion of satisfied customers = 90%

n = sample of customers = 80

Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( $\hat p \leq$ 80%)

P( $\hat p \leq$ 80%) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\leq$ $\frac{0.80-0.90}{\sqrt{\frac{0.80(1-0.80)}{80} } }$ ) = P(Z $\leq$ -2.24) = 1 - P(Z < 2.24)

= 1 - 0.9875 = 0.0125

The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.

8 0

4 years ago

HELP! Zoom in Describing functions with equations tables and graphs

Dvinal [7]

378. Comparing the each batch, there is a difference of 18 for each batch. So 7*18= 126, then add that to 252; you'll get 378.

(ex 198-180=18; 216-198=18; etc)

hope that helps

3 0

3 years ago

 (6 pts) The average age of CEOs is 56 years. Assume the variable is normally distributed. If the SD is four years, find the pr

Alenkinab [10]

Answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is 0.334.

Step-by-step explanation:

We have a normal distribution with mean=56 years and s.d.=4 years.

We have to calculate the probability that a randomly selected CEO have an age between 50 and 55.

We have to calculate the z-value for 50 and 55.

For x=50:

$z=\frac{x-\mu}{\sigma}=\frac{50-56}{4}=\frac{-6}{4}= -1.5$

For x=55:

$z=\frac{x-\mu}{\sigma}=\frac{55-56}{4}=\frac{-1}{4}=-0.25$

The probability of being between 50 and 55 years is equal to the difference between the probability of being under 55 years and the probability of being under 50 years:

$P(50$

5 0

4 years ago

Find the surface area of the rectangular prism. 2 cm 6 cm 3 cm [?] sq cm

Vadim26 [7]

Answer:

60

Step-by-step explanation:

3 0

3 years ago