Answer:
Step-by-step explanation:
So we have the equation:
First, distribute the left side:
Add values on the left side:
Add 7 to both sides. The right side cancels:
Subtract 2x from both sides. The left side cancels:
Divide both sides by -6:
Therefore, x equals -3.
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
Answer:
91
Step-by-step explanation:
In this question, the important information we get from this is that the stage can support 12,750 students. We are asked, if the average weight of a student is 140 pounds, what is the maximum number of students that can be on the stage safely?
To solve, we simply divide 12,750 by 140.
We get 91.07 as our answer. Since we are considering the maximum number of students, then we must round 91.07 to the nearest whole number which would be 91.
The maximum number of students who could safely be on the stage is 91.
The answer is -4 2/3
Explanation : The elevator is at 0, and went below ground level 90 feet, that would be -90, then it went up 20 feet, which would be -90 + 20 = -70
-70 ft / 15sec = - 4 2/3
I am not sure about the ground level and negative difference but that it is what I was taught. Below ground level is negative and above is positive. Therefore the elevator traveled up and it traveled -4 2/3 per second.
It so either 4 2/3 or - 4 2/3 but pretty sure it is - 4 2/3.
:)))
Please take 1 minute, and really read the example solution
under problem #12. All of the other eight problems on the
sheet are solved in exactly the same way:
Multiply each side of the equation by the denominator of
the fraction ... the number under the variable (the letter).
This easy step will get you the answer to each of the
eight problems.
I can't help noticing that the title of the sheet is 'extra PRACTICE' .
If someone handed you the answers, then you would not get the
practice. That would be just like stealing from you, and would be
just plain mean.
