All categories

3 years ago

Trigonometry Special Right Triangles Find the exact value of sec 60* - cosec 30* - sin 0*.

Mathematics

1 answer:

evablogger [386]3 years ago

8 0

Answer:

Step-by-step explanation:

cos(60) = ½

sec(60) = 2

sin(30) = ½

cosec(30) = 2

sin(0) = 0

2 - 2 - 0 = 0

You might be interested in

What is equivalent to the following expression select all that apply.

STALIN [3.7K]

C.6 3 becaue im trying to get point dont lissten to me

8 0

2 years ago

Read 2 more answers

What are the solutions to the quadratic equation below? X^2-8x+16

leva [86]

(₋4)²

how i got it -

1st i used the sum-product pattern

x² - 8x + 16

x² -4-4+16

then, found the common fact from the two pairs

x² - 4 - 4 + 16

(-4) - 4(-4)

rewrite in factored form

(x-4)-4(-4)

(-4) (-4)

combine to a square

(-4) (-4)

4 0

2 years ago

Read 2 more answers

Helpppppppppppooooo :p

garri49 [273]

Answer:

1) c. 10

2) a. 1 and 18

3) d. 17

4) I think it's actually 12 but I don't know

8 0

3 years ago

Expand the given power by using Pascal’s triangle. (9a - 10b)^6

xxMikexx [17]

Answer:

$531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

Step-by-step explanation:

1 n=0

1 1 n=1

1 2 1 n=2

1 3 3 1 n=3

1 4 6 4 1 n=4

1 5 10 10 5 1 n=5

1 6 15 20 15 6 1 n=6

This is where n is the exponent in

$(x+y)^n$ .

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

Now we want to expand:

$(9a-10b)^6$ or we we can rewrite as $(9a+(-10b))^6$ .

Let's replace $x$ with $(9a)$ and $y$ with $(-10b)$ in the expansion:

$(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6$

$((9a)+(-10b))^6$

$=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6$

Let's simplify a bit:

$=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6$

$=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6$

8 0

3 years ago

Amit solved the equation StartFraction 5 over 12 EndFraction = Negative StartFraction x over 420 EndFraction for x using the ste

melomori [17]

Answer:

-AKA-

The product of StartFraction 5 over 12 EndFraction and –420 should have been the value of x.

-AKA-

The product of 5/12 and –420 should have been the value of x.

Step-by-step explanation:

i did it on edge 2020

see..........

hope it helps :)

7 0

3 years ago

Read 2 more answers