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2 years ago

Multiply. Do not round your answer. 6.9 × 1.221 = Thanks :D

Mathematics

1 answer:

Ann [662]2 years ago

6 0

Answer:

8.4249 ur answer....

hope it helps

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Volume= Help me please thanks so much asap

hjlf

Answer:

600

Step-by-step explanation:

since it is a right triangle based pyramid, 2 of them will make a cube. so, it is bwh / 2.

base = 24

width = 10

height = 5

volume = 1200

volume of pyramid = 600

5 0

1 year ago

Two ways to write 15-b

GaryK [48]

The Answer: (-b + 15) (15 - b)

7 0

3 years ago

Write the equation of a square root function that has the following graph.

Anastaziya [24]

9514 1404 393

Answer:

g(x) = √(x -5) +7

Step-by-step explanation:

To translate the graph of f(x) by h units horizontally and k units vertically, the function is transformed to ...

g(x) = f(x -h) +k

To translate f(x) = √x by 5 units horizontally and 7 units vertically, the function is transformed to ...

g(x) = √(x -5) +7

6 0

2 years ago

Please answer this friends I am stuck ?

goblinko [34]

Answer:

10°C average temperature

Step-by-step explanation:

Average Temperature = Lowest + 17

= -7 + 17

= 17 - 7

= 10°C average temperature

4 0

2 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

2 years ago

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