Can you help me please I pay you £50

Find the area. The figure is not drawn to scale.

s2008m [1.1K]

I believe the answer is B: 13.2 because to find the area of a triangle you do l x w x 1/2.

8 x 3.3 x 1/2 = 13.2.

7 0

2 years ago

Li Ping says a square with 3 inch sides has greater area than a parallelogram that is not a square but has sides that have the s

Kipish [7]

Answer:

Li Ping's statement makes sense.

Step-by-step explanation:

The area of a square with side lengths a inches is given by, $A_1 = a^{2}$ .

Now, the area of a parallelogram with equal sides a inches, which is not a square is given by, $A_2 = ah$ , where, h is the perpendicular distance between the opposite sides.

See the diagram attached.

Since a is the hypotenuse of as right triangle with height h, hence, a > h.

So, $A_1 > A_2$

Therefore, Li Ping's statement makes sense. (Answer)

8 0

2 years ago

Please help ASAP!! Will Mark Brainiest

mr Goodwill [35]

I am pretty sure its JT

7 0

2 years ago

John buys a computer with a 20% discount. If he paid $760 for the computer, how much was the discount?

Mumz [18]

If there was 20% taken off you add 20% back on and that is how you will get your answer. So take 760 plus the 20% which gives you 912 dollars

8 0

2 years ago

Read 2 more answers

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

2 years ago