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Eva8 [605]
3 years ago
6

Can someone simplify this for me please (2x^2+4x+1)+(3x^2+6x+5)

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

Answer:

5x^2+10x+6

Step-by-step explanation:

add 2x^2 & 3x^2

add 4x and 6x

add 1 and 5

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4 0
3 years ago
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A bag of marbles contains 4 green marbles, 3 blue marbles, 2 red marbles, and 5 yellow marbles. How many total possible outcomes
asambeis [7]

Answer:

4, because if you chose any one from the 4 green marble the answer is 1 because all are same coloured, you can chose one green or one red or one blue or one yellow

Step-by-step explanation:

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8 0
3 years ago
If p(x)=x2-1 and q(x)=5(x-1 which expression is equivalent to (p-q)(x)
Veseljchak [2.6K]

p(x)=x^2-1\\\\q(x)=5(x-1)\\\\(p-q)(x)=p(x)-q(x)=(x^2-1)-5(x-1)



Answer: (x2 - 1) - 5(x - 1)

7 0
3 years ago
Find an explicit formula for the arithmetic sequence -31,-27,-23,-19,...
Yuri [45]
First term (a) = -31

Common Difference (d) = -27 - (-31) = -27 + 31 = 4

nth term = a + (n - 1)d = -31 + (n - 1)4 = -31 + 4n - 4 = 4n - 35

Hence, the formula is 4n - 35.
6 0
3 years ago
Lim x → 0 sin3x)/5x^3 -4
JulsSmile [24]
\bf \lim\limits_{x\to 0}\ \cfrac{sin^3(x)}{5x^3}-4
\\ \quad \\\\ \cfrac{sin^3(x)}{5x^3}-4\implies \cfrac{[sin(x)]^3}{5x^3}-4
\\ \quad \\
 

\cfrac{[sin(x)]^3}{x^3}\cdot \cfrac{1}{5}-4
\\ \quad \\
thus
\\ \quad \\
\lim\limits_{x\to 0}\cfrac{[sin(x)]^3}{x^3}\cdot \lim\limits_{x\to 0}\cfrac{1}{5}-4\qquad \boxed{recall \qquad \lim\limits_{x\to 0} \cfrac{sin(x)}{x}\implies 1}
\\ \quad \\
1\cdot \cfrac{1}{5}-4
8 0
3 years ago
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