Need help please thanks you

A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost

NikAS [45]

Answer:

47 meetings

Step-by-step explanation:

1. You know the company generates 100,000 dollars in profits, and pays 50,000 dollars to host the event, therefore, subtract both numbers to determine how much profit they make.

100,000 - 50,000 = 50,000 dollars

2. You now know that company generates 50,000 dollars in profits for each meeting

3. You also know that the company is aiming for a profit of 2.35 million, so you would divide the the goal by the total profits per meeting

2,350,000/50,000 = 47

It takes 47 meetings for the company to reach their goal.

4 0

3 years ago

PLEASE HELP...PLEASEEEEEEEEEEE

Nata [24]

Answer:

This is not a good model because the residual plot becomes thicker at the end

6 0

3 years ago

Option 1:<br><br> Find x. Show all work.

Ronch [10]

Using law of cosines:

Cos(angle) = adjacent/ hypotenuse

Cos(22) = 12/x

Rewrite to get:

X = 12/cos(22)

Simplify:

X = 12.9424

Round the answer as needed.

5 0

2 years ago

Read 2 more answers

A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),

prisoha [69]

24/36 which simples down to 2/3 ever 2 in 3 roles

5 0

3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

7 0

3 years ago