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lisabon 2012 [21]
3 years ago
15

Enter the fraction as a decimal and as a percent.

Mathematics
1 answer:
Fofino [41]3 years ago
8 0
.625
62.5%
to find decimal divide top # by bottom # and them move decimal 2 places to the right
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A photo of a painting measured 13 x 17 inches the scale of the photo to the original painting is 1 inch to 3 inches. What is the
bulgar [2K]

Answer:

  29 × 51 inches

Step-by-step explanation:

If the scale is ...

  photo : painting = 1 : 3

then each dimension of the painting is 3 times the corresponding dimension of the photo. The painting is (3×13) by (3×17) inches, or 39 × 51 inches.

5 0
3 years ago
Point A is the point of concurrency of the angle bisectors of ΔDEF. Point A is the point of concurrency of triangle D E F. Lines
fiasKO [112]

Answer:

  ZA = 3 cm

Step-by-step explanation:

Point A is the incenter of the triangle, so segments AX, AY, and AZ are radii of the circle. They are all the same length, given as 3 cm and confirmed by 3-4-5 right triangle AYD.

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8 0
3 years ago
Given the right triangle shown below.if Cos A =15/17 and tan A=8/15 which of the following represents the length of BC
otez555 [7]

Answer:

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

Step-by-step explanation:

Given:

Consider a right triangle ABC, Such that

\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}

To Find:

BC = ?

Solution:

In Right Angle Triangle ABC, Cosine and Tangent identity

\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\

\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

BUT,

\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15} ....Given

On Comparing,

Adjacent side to angle A = AB = 15

Opposite side to angle A = BC = 8

Hypotenuse = AC =17

Also Pythagoras theorem is Satisfies,

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

(\textrm{Hypotenuse})^{2} = 17^{2}=289

(\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}=15^{2}+8^{2}=289

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

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3 years ago
Triangle 4.5 x4.5x4.5x4
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If 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?
andreev551 [17]
Tan ( A - B ) = ( tan A - tan B ) / ( 1 + tan A tan B )
tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2)  / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B )  - correct 
8 0
3 years ago
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