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Reptile [31]
3 years ago
12

Simplify the expression. 8k - 2(4 - 3k)

Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer

14k-8

Step-by-step explanation:

combine like terms

DIA [1.3K]3 years ago
6 0

Answer:

14k-8

Step-by-step explanation:

8k - 2(4-3k)

distributive property

8k - 8  + 6k

add like terms

8k + 6k -8

14k - 8

14k - 8

If anyone will look for the value of k, k is 4/7 btw but the answer to simplify the expression would be 14k-8.

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I need some help plz
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B

Step-by-step explanation:

The most reasonable one is B because its 7 for side B and the rest for B are either bigger or equal to the given number

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What is 2 1/8 take away 1/2​
goblinko [34]

The equation is 2\frac{1}{8} - \frac{1}{2} .

1/2 is equivalent to 4/8, and 2 1/8 is equal to 17/8. (two full sets of 8 + 1 = 8 + 8 + 1, or 17)

The new equation is \frac{17}{8} -\frac{4}{8} . Subtract the numerators.

17 - 4 = 13 or 13/8

The improper fraction \frac{13}{8} simplifies to 1\frac{5}{8} .

<h2>Answer:</h2>

1\frac{5}{8}

Hope this helps :)

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4 years ago
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Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
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