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Varvara68 [4.7K]
3 years ago
15

the half life of polonium is 139 days. you have a brand new sample of polonium that will not be useful to you after 80% of the m

aterial hasdistegraded. For how many days will you be able to use the polonium?
Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

The half-life of Po is 139 days, so its decay rate is

0.5 = e^(139k)  ==>  k = ln(0.5)/139

After some time t, 80% of the material will have decayed and you'll be left with a sample 20% of its original mass:

0.2 = e^(kt)  ==>  t = ln(0.2)/k = ln(0.2)/ln(0.5) * 139 = 322.748

so your sample is usable for about 323 days.

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What’s a equation for one Half and one six
AfilCa [17]

One half would be 1/2

One six would be 1/6


5 0
3 years ago
Multiply these polynomials and simplify. Enter your response in standard form (-6y + 8y4 – 5)(y2 – 11y)
Mashutka [201]

Answer:  The required simplified answer in standard form is 8y^6-88y^5-6y^3+61y^2+55y.

Step-by-step explanation:  We are given to multiply the following polynomials and write the answer is standard form :

M=(-6y+8y^4-5)(y^2-11y)~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To multiply the given polynomials, we need to multiply each term of one polynomial to each term of the other polynomial.

From (i), we have

M\\\\=(-6y+8y^4-5)(y^2-11y)\\\\=y^2(-6y+8y^4-5)-11y(-6y+8y^4-5)\\\\=-6y^3+8y^6-5y^2+66y^2-88y^5+55y\\\\=8y^6-88y^5-6y^3+61y^2+55y.

Thus, the required simplified answer in standard form is 8y^6-88y^5-6y^3+61y^2+55y.

3 0
3 years ago
How do you solve this?​
blondinia [14]

Answer:

≈ 3.6 x 10^1

Step-by-step explanation:

= (6.05 x 3.05) x 10^(5+4) / (4.27 x 1.2) x 10^(4+4)

= 18.4525 x 10^9 / 5.124 x 10^8

= (18.4525 / 5.124) x 10^(9-8)

≈ 3.6 x 10^1

6 0
2 years ago
12. How many students scored at least 60 on the test?<br> a) 3<br> b) 4<br> c) 11<br> d) 7
Troyanec [42]
4
i don’t have an explanation
7 0
3 years ago
28.
Artyom0805 [142]

Answer:

50

Step-by-step explanation:

30% * n = 15

Change to decimal form

.30 *n = 15

Divide each side by .30

.30n/.30 = 15/.30

n =50

The number is 50

7 0
3 years ago
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