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2 years ago

Please help me asap!!!!!

Mathematics

2 answers:

lina2011 [118]2 years ago

8 0

Answer: A!!! Hope it helped!

Airida [17]2 years ago

7 0

Answer:

y=0.5x+3

Step-by-step explanation:

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What is the lcd of 8/15 11/30 and 3/5

pogonyaev

Answer:

LCD(8/ 15 , 11/ 30 , 3/ 5 ) = LCM(15, 30, 5) = 2×3×5 = 30

Step-by-step explanation:

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2 years ago

James is reading a book that is 1400 pages he will read the same number of pages each day if he reads the book in 7 days how man

Novay_Z [31]

He will read 200 pages a day.

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2 years ago

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Please help - Solve<br> -103=6x+17

Mazyrski [523]

Answer:

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2 years ago

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Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

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2 years ago

2log(2a - 1) = 0<br> How

Kryger [21]

Answer:

Step-by-step explanation:

$2\log(2a-1)=0\\\\\text{Domain:}\\\\2a-1>0\qquad\text{add 1 to both sides}\\2a-1+1>0+1\\2a>1\qquad\text{divide both sides by 2}\\\dfrac{2a}{2}>\dfrac{1}{2}\\\boxed{a>0.5}\\============================\\\\2\log(2a-1)=0\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup\log(2a-1)}{2\!\!\!\!\diagup}=\dfrac{0}{2}\\\\\log(2a-1)=0\qquad\text{use}\ \log_ab=c\iff b=a^c\\\\\log(2a-1)=\log10^0\\\\\log(2a-1)=\log1\iff2a-1=1\qquad\text{add 1 to both sides}\\\\2a-1+1=1+1\\\\2a=2\qquad\text{divide both sides by 2}\\\\\dfrac{2a}{2}=\dfrac{2}{2}\\\\a=1\in D$

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2 years ago