<span> Here are the steps, you fill in the missing parts.
A. The given ratio is:
2 adults per 9 students or the fraction 2/9
Now put that fraction 2/9=x/171 in other words, how many adults (x) for 171 students?
can you cross multiply and get 9x=342
and solve for x?
How you have the number of students and the number of adults.
B. for food multiply $6 times the total number of people.
C. for tickets multiply 4.50 times the student number and
7.50 times the adult number.
D. for the bus parking fee multiply .04 times you total answer in part C.
Now add up the food, tickets, bus parking and I think you have what Mr. Williams has to budget. </span>
Answer:
5, 7 , 7 and 11.
Step-by-step explanation:
I don't quite understand the Romanian but I'm pretty sure you want to find the numbers whose Lowest Common Multiple is 385 and whose product is 2695. Find the factors of 2695:-
5 2695
7 539
7 77
11
2695 = 5*7*7*11.
Lowest common multiple = 5*7*11 = 385.
1 to 23
if 23 people put in $5 you get $115 as a total.
so 1:23 are the odds
Part A
Answer: The common ratio is -2
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Explanation:
To get the common ratio r, we divide any term by the previous one
One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2
Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time
Side Note: each term is multiplied by -2 to get the next term
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Part B
Answer:
The rule for the sequence is
a(n) = (-2)^(n-1)
where n starts at n = 1
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Explanation:
Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio
The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)
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Part C
Answer: The next three terms are 16, -32, 64
-----------------------------------
Explanation:
We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms
-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64
showing that the next three terms are 16, -32, and 64
An alternative is to use the formula found in part B
Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier
Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier
Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier
while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
14 because it is half of the width around the pond.
