<u><em>When x = -2</em></u>, f(x) = -7(-2) + 3 = 14 + 3
<u><em>x = 17</em></u>
<u><em>When x = 5</em></u>, f(x) = -7(5) + 3 = -35 + 3
<u><em>x = -32</em></u>
All you have to do to solve the function is substitute the value of x into the equation.
Answer:
+1/2
Step-by-step explanation:
If the slope of the given line is -2, the slope of a line perpendicular to the given line is the negative reciprocal of -2, or +1/2.
Answer:
good
those desert people ought to use less water
A. 400*45.2=400*45+400*0.2=18000+80=18080
B. 14.9*100=15*100-0.1*100=1500-1=1490
C. 76.2*200=76*200+0.2*200=15200+4=15204
<u>Annotation</u>General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.
One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)
The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)
Plug the d-v-t relationship to the second equationd₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262
Plug the v₁ as (v₂+5) from the first equation2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.Find the velocity of the first car, use the first equationv₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.
Answer

