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nata0808 [166]
3 years ago
9

\frac{2}{3} = m - \frac{5}{3} " alt=" \frac{2}{3} = m - \frac{5}{3} " align="absmiddle" class="latex-formula">

​
Mathematics
1 answer:
EleoNora [17]3 years ago
4 0

7/3 or if you change it to a mixed number it will be 2 1/3

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Please help! (: I know the middle one is 3
Olenka [21]

<u><em>When x = -2</em></u>, f(x) = -7(-2) + 3 = 14 + 3

<u><em>x = 17</em></u>

<u><em>When x = 5</em></u>, f(x) = -7(5) + 3 = -35 + 3

<u><em>x = -32</em></u>

All you have to do to solve the function is substitute the value of x into the equation.

5 0
4 years ago
Read 2 more answers
, 4), perp. to y=-2x - 4​
AVprozaik [17]

Answer:

+1/2

Step-by-step explanation:

If the slope of the given line is -2, the slope of a line perpendicular to the given line is the negative reciprocal of -2, or +1/2.

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3 years ago
Due to environmental considerations, homeowners in a particularly dry area have been asked to use less water than usual. One hom
Dmitriy789 [7]

Answer:

good

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3 0
3 years ago
Calculate the product using partial products:
Archy [21]
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5 0
3 years ago
Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
Mashutka [201]
<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
7 0
4 years ago
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