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Rudik [331]
3 years ago
5

A rectangular garden is 6 feet by 4 feet. There is a sidewalk of uniform width around the garden. The area of the sidewalk and t

he garden together is 48 ft2. What is the width of the sidewalk? A) 1 foot B) 2 feet C) 4 feet D) 6 feet
Mathematics
1 answer:
Reil [10]3 years ago
3 0

Answer:

The width of the sidewalk is 1 feet

Step-by-step explanation:

We are given

A rectangular garden is 6 feet by 4 feet

Let's assume width of the side of walk is x feet

Since, there is a sidewalk of uniform width around the garden

now, we can find width and height of the garden and side walk

L=6+2x

W=4+2x

now, we can find total area

Total area is

=L\times W

now, we can plug values

=(6+2x)\times (4+2x)

The area of the sidewalk and the garden together is 48 ft^2

so, we can set it equal and then we can solve for x

(6+2x)\times (4+2x)=48

24+20x+4x^2=48

4x^2+20x-24=0

we can factor out 4

4(x^2+5x-6)=0

(x+6)(x-1)=0

x=-6,x=1

we know that dimension can never be negative

so, we will only consider positive

x=1

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What is the area of a parallelogram if the coordinates of its vertices are (0, -2), (3, 2), (8,2), and (5,-2)?
Llana [10]

Answer:

The area of the parallelogram is 20 units²

Step-by-step explanation:

* Lets explain how to solve the problem

- The vertices of the parallelogram are (0 , -2) , (3 , 2) , (8 , 2) , (5 , -2)

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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